(8x^-2y^3)/(4x^1/2y^-2)

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Solution for (8x^-2y^3)/(4x^1/2y^-2) equation: 


D( x )

((4*x^1)/2)*y^-2 = 0

x = 0

((4*x^1)/2)*y^-2 = 0

((4*x^1)/2)*y^-2 = 0

((4*x)/2)*y^-2 = 0

2*x*y^-2 = 0 // : 2*y^-2

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(8*x^-2*y^3)/(((4*x^1)/2)*y^-2) = 0

(8*x^-2*y^3)/(((4*x)/2)*y^-2) = 0

4*x^-3*y^5 = 0 // : 4*y^5

x^-3 = 0

x należy do O

x belongs to the empty set

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